Acceleration Due To Gravity Calculator

Acceleration Due To Gravity Formula:

\[ g = \frac{G \times M}{r^2} \]

Acceleration Due To Gravity (g):

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1. What is Acceleration Due To Gravity?

Acceleration due to gravity (g) is the acceleration experienced by an object due to the gravitational force exerted by a massive body. It represents the rate at which an object's velocity changes when falling freely under the influence of gravity.

2. How Does the Calculator Work?

The calculator uses the gravitational acceleration formula:

\[ g = \frac{G \times M}{r^2} \]

Where:

\( G \) — Gravitational constant (6.67430 × 10⁻¹¹ m³/kg s²)
\( M \) — Mass of the celestial body (kg)
\( r \) — Distance from the center of mass (m)

Explanation: This formula calculates the gravitational acceleration at a given distance from the center of a massive object, based on Newton's law of universal gravitation.

3. Importance of Gravity Calculation

Details: Calculating gravitational acceleration is crucial for space missions, satellite operations, understanding planetary physics, and various engineering applications where gravitational effects must be considered.

4. Using the Calculator

Tips: Enter the gravitational constant (default is Earth's value), mass of the celestial body in kilograms, and distance from the center in meters. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What is the standard value of g on Earth's surface?
A: Approximately 9.8 m/s², though it varies slightly with latitude and altitude.

Q2: How does gravity change with distance?
A: Gravity follows an inverse-square law - it decreases with the square of the distance from the center of mass.

Q3: Why is the gravitational constant so small?
A: The gravitational constant is a fundamental physical constant that reflects the relative weakness of gravitational force compared to other fundamental forces.

Q4: Can this calculator be used for any celestial body?
A: Yes, by inputting the appropriate mass and distance values, you can calculate gravitational acceleration for any object.

Q5: How accurate is this calculation?
A: The calculation provides theoretical Newtonian gravity. For extreme precision (near black holes or relativistic speeds), general relativity corrections are needed.